Understanding the Reaction Between Sodium Hydroxide and Iron(II) Sulfate

Unpack the balanced word equation for the reaction between sodium hydroxide and iron(II) sulfate. Discover its significance and implications in IGCSE chemistry studies while enhancing your understanding of double displacement reactions.

Multiple Choice

What is the balanced word equation for the reaction between sodium hydroxide and iron(II) sulfate?

Explanation:
The balanced word equation for the reaction between sodium hydroxide and iron(II) sulfate is accurately represented by the option stating that sodium hydroxide reacts with iron(II) sulfate to form iron(II) hydroxide and sodium sulfate. This is correct because: When sodium hydroxide (NaOH), a strong base, interacts with iron(II) sulfate (FeSO4), which is a salt of iron in the +2 oxidation state, the products formed involve iron in its +2 oxidation state, specifically as iron(II) hydroxide (Fe(OH)2). This aligns with the principles of double displacement reactions, where the cations and anions exchange partners. The formation of sodium sulfate (Na2SO4) also occurs as part of this reaction, maintaining the charge balance and adhering to the conservation of mass. Therefore, this choice accurately represents the complete reaction where both reactants properly yield their corresponding products without any oxidation state changes for iron, leading to the conclusion that the option specifying iron(II) hydroxide correctly describes this reaction. Other options mistakenly refer to iron(III) hydroxide or improperly label the compounds involved, which would not accurately reflect the chemistry of the initial reactants. Thus, recognizing the iron’s

When you're gearing up for the IGCSE Chemistry exam, understanding the key reactions like the one between sodium hydroxide and iron(II) sulfate can make a huge difference. Let’s break it down: the balanced word equation for this chemical reaction is “sodium hydroxide + iron(II) sulfate —> iron(II) hydroxide + sodium sulfate." Sounds straightforward, right? But why is it important?

Well, sodium hydroxide (NaOH) is a strong base, and when it meets iron(II) sulfate (FeSO4), things start to get interesting! You see, these two compounds engage in a double displacement reaction, where cations and anions swap partners much like a dance at a party. So, instead of cha-cha-ing or waltzing, they form iron(II) hydroxide (Fe(OH)2) and sodium sulfate (Na2SO4).

Now, let’s talk implications! Sodium hydroxide keeps iron in its +2 oxidation state throughout the reaction. This is super handy when studying iron's role in various processes. Understanding that no oxidation state changes for iron happen here reinforces the law of conservation of mass — everything balances out perfectly! When you're reviewing for the IGCSE, these concepts matter.

You may encounter some other options that mention iron(III) hydroxide or mislabel the compounds involved. And let me tell you, that could throw you off track faster than you can say “catalyst!” Always ensure that the compounds you identify align with the correct oxidation states and product types for clarity and accuracy.

Here’s the kicker: mastering this reaction can bolster your confidence and understanding of other related concepts, such as precipitation reactions, solubility rules, or even other notable double displacement reactions. It sets the stage for more complex topics you’ll tackle later on.

So, the next time you find yourself stuck on a question about sodium hydroxide and iron(II) sulfate or wish to explore more reactions, remember this particular equation. It’s a fundamental part of your chemistry toolkit! You know what? Being clear on these basics helps pave your way through the complexities of chemistry.

Take a moment now and review the principles we discussed. Make sure to keep your notes handy for quick referencing, especially as you practice for your exams. And remember, learning chemistry doesn’t have to feel overwhelming. Sometimes, it's just about piecing together the puzzle one reaction at a time!

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